Example 3

Titan - P₀ = 1.6 bar, g= 1.36 m s^-2 and Mc = P₀ /g = 1.6 x 10⁵ Pa / 1.36 m s^-2 = 1.2 x 10⁵ kg m^-2

In Class 2 we already calculated

H_T/H_E=(T_T/T_E)(g_E/g_T) ~(125 Kelvin / 250 Kelvin)(980 cm s^-2 / 135 cm s^-2 )~3.5

So...... that means r(Titan)/r(Earth) = Mc(Titan)/Mc(Earth) x H(Earth)/H(Titan) = 12/3.5 ~3.4

or, another way....

r(Titan)/r(Earth) = P(Titan)/P(Earth) x T(Earth)/T(Titan) = 1.6 x (270/125) ~3.5